-320=-b^2+32b

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Solution for -320=-b^2+32b equation:


Simplifying
-320 = -1b2 + 32b

Reorder the terms:
-320 = 32b + -1b2

Solving
-320 = 32b + -1b2

Solving for variable 'b'.

Reorder the terms:
-320 + -32b + b2 = 32b + -32b + -1b2 + b2

Combine like terms: 32b + -32b = 0
-320 + -32b + b2 = 0 + -1b2 + b2
-320 + -32b + b2 = -1b2 + b2

Combine like terms: -1b2 + b2 = 0
-320 + -32b + b2 = 0

Factor a trinomial.
(-8 + -1b)(40 + -1b) = 0

Subproblem 1

Set the factor '(-8 + -1b)' equal to zero and attempt to solve: Simplifying -8 + -1b = 0 Solving -8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1b = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1b = 0 + 8 -1b = 0 + 8 Combine like terms: 0 + 8 = 8 -1b = 8 Divide each side by '-1'. b = -8 Simplifying b = -8

Subproblem 2

Set the factor '(40 + -1b)' equal to zero and attempt to solve: Simplifying 40 + -1b = 0 Solving 40 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-40' to each side of the equation. 40 + -40 + -1b = 0 + -40 Combine like terms: 40 + -40 = 0 0 + -1b = 0 + -40 -1b = 0 + -40 Combine like terms: 0 + -40 = -40 -1b = -40 Divide each side by '-1'. b = 40 Simplifying b = 40

Solution

b = {-8, 40}

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